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Module 4
Variation and Problem Solving
Question | Answer |
---|---|
If the y varies directly as x, find the constant of variation (k) and the direct variation equation if y=2 when x=10 | k=1/5 y=1/5x |
If the y varies directly as x, find the constant of variation (k) and the direct variation equation if y=10 when x=90 | k=1/9 y=1/9x |
If the y varies directly as x, find the constant of variation (k) and the direct variation equation if y=75 when x=15 | k=5 y=5x |
If the y varies inversely as x, find the constant of variation (k) and the inverse variation equation if y=12 when x=10 | k=120 y=120/x |
If the y varies inversely as x, find the constant of variation (k) and the inverse variation equation if y=50 when x=5 | k=250 y=250/x |
If the y varies inversely as x, find the constant of variation (k) and the inverse variation equation of y=2 when x=4 | k=8 y=8/x |
Find the constant of variation (k) and the variation equation: y varies jointly as x and the cube of z; y=120 when x=5 and z=2 | k=3 y=3xz^3 |
Suppose x varies jointly with y and the square root of z. When x=-18 and y=2, then z=9. Find y when x=10 and z=4 | k=-3 y=-5/3 |
If x varies directly as y and inversely as z, and x = 10 when y = 5 and z = 3, for what value of z will x = 3 and y = 4? | k=6 z=8 |
Beam: 1/2 ft wide, 1/3 ft high, 10 ft long; supports 12 tons Beam: 2/3 ft wide, 1/2 ft high, 16 ft long; supports ? | k=2160 Supports 22.5 tons |
If y varies directly with x and inversely with z2. If y = 6, when x = 4 and z = 3, what is the value of y when x = 2 and z = 4? | k=13.5 y=27/16 |