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BC Calc - Unit 6
Question | Answer |
---|---|
∫u'e^u | e^u + C |
∫f'(g(x)) ⋅ g'(x) | f(g(x)) +C |
∫1/√1-x^2 | arcsinx + C |
∫-1/√1-x^2 | arccosx + C {or} -arcsinx + C |
∫1/1+x^2 | arctanx + C |
∫-1/1+x^2 | arccotx + C {or} -arctanx + C |
∫1/|x|√x^2-1 | arcsecx + C |
∫-1/|x|√x^2-1 | arccscx + C {or} arcsecx + C |
A Right Riemann Sum In An Over-Approximation When... | the graph is increasing |
A Left Riemann Sum In An Over-Approximation When... | the graph is decreasing |
A Right Riemann Sum In An Under-Approximation When... | the graph is decreasing |
A Left Riemann Sum In An Under-Approximation When... | the graph is increasing |
Steps To Find f'(x) When f(x)=∫tdt | derivative and integral cancel, plug in top limit for t, solve |
Integration By Parts Theorem | ∫udv = uv - ∫vdu |
Sigma Notation | ∑ = sigma notation // n=upper bound // i=index // # i equals=lower bound |
EVT | every continuous function on [a,b] has both an absolute maximum and minimum |
In Word Problems, f(x) Is... | a number |
In Word Problems, f'(x) Is... | a rate |
In Word Problems, f''(x) Is.. | a rate of a rate |
Absolute Minimums & Maximums Can Occur At... | endpoints & critical values |
∫x^-1dx Is Equal To... | ∫1/xdx {or} ln|x| |
When Writing The Solution To An Indefinite Integral, Always Add... | + C |
∫a^xdx | (1/lna)(a^x) + C |
∫f(u)u'dx | f(u) + C |
∫(a^u)(u')dx | (1/lna)(a^u) + C |
∫du/√a^2 - u^2 | arcsin(u/a) + C |
∫du/a^2 + u^2 | (1/a) ⋅ arctan(u/a) + C |
∫du/u√u^2-a^2 | (1/a) ⋅ arcsec(|u|/a) + C |
Steps To Integrate With Long Division | divide numerator by denominator, plug answer back into intergal, solve integral |
Completing The Square | x^2+bx+c = x^2 + bx + (b/2)^2 - (b/2)^2 + C = (x+b/2)^2 - (b/2)^2 + C |
When Picking The U In An Integration By Parts, You Should Use... | L.I.A.T.E. |
L.I.A.T.E. Stands For... | logarithm, inverse trig, algebraic, trigonometric, exponential |
Tabular Method | first column: alternating signs starting with + // second column: derive u-value until 0 // third column: intergrate dv-value |
Linear Factors | (a*x + b*) / (a**x + b**) (a***x + b***) = [A / (a**x + b**)] + [B / (a***x + b***) |