Primary Exposure Factors
Quiz yourself by thinking what should be in
each of the black spaces below before clicking
on it to display the answer.
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| show | *ma *kVp *time *SID
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| mA x time= | show 🗑
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| what is the k shell binding energy for bone | show 🗑
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| what does mA control | show 🗑
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| what does kVp control | show 🗑
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| what is the purpose of technique charts | show 🗑
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| what are the two types of technique charts | show 🗑
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| what happens with a variable kVp chart | show 🗑
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| what happens with a fixed kVp chart | show 🗑
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| no amount of _______ can make up for inadequate _______ | show 🗑
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| what equipment is used to develop technique charts | show 🗑
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| show | *infants(0-2 yrs)-use 1/4 of mAs
*preschool(2-6 yrs)-use 1/2 of mAs
*school age(6-12 yrs)-use 3/4 of mAs
*teens (>12)-no change
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| what are the rules of thumb regarding technique with a cast | show 🗑
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| show | *14 x 17 to 10 x 12- 40% more mAs or +5 kVp
*14 x 17 to 8 x 10- 60% more mAs or +10 kVp
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| show | motion/recorded detail
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| show | *mA x time
*mA1/mA2=t2/t1
*indirect relationship between mA and time
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| show | *mAs1/mAs2=SID1 squared/SID2 squared
*applied when unable to get optimal distance
*based upon inverse square law
*if no time just use mA to calculate
*if no mA just use time to calculate
**distance must always be squared
*direct relationship
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| what is the 15% kVp rule | show 🗑
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| show | I1/I2=D2 squared/D1 squared
*the intensity of radiation is inversely related to distance squared
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| show | *image size/object size *percent mag=oid/sod *mag factor=sid/sod
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| what are the grid conversions for mAs | show 🗑
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| what are the grid conversions for kVp | show 🗑
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| how do you calculate screen conversion | show 🗑
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| show | *photographic effect *numerical representation of optical density *PE= (mAxtxkVp squared/SID squared)x IR/grid *if factor missing, leave out of equation
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| show | *single phase to 3-phase(1/2 mAs or drop 10 kVp) *3-phase to single phase(2x mAs or +10 kVp)
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| what is the advantage of 3 phase equipment | show 🗑
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| show | 3 phases of alternating current, rectifiers eliminate negative current allowing more output
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