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Treatment Planning Test

Enter the letter for the matching Answer
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1.
Electron 90% Isodose line
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2.
Hinge Angle
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3.
SSD
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4.
LDR isotopes deliver at a dose rate =_______cGy/min
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5.
What is the half-life of radium-226?
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6.
A 45 degree wedge is inserted into a field to modify the isodose curve. The toe section will allow (greater or lesser) intensity in part of the beam.
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7.
The dose rate on a linear accelerator is 102.4 cGy/Min at 100 cm. What is the dose rate at 85.5 cm?
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8.
HDR isotopes deliver at a dose rate =_______cGy/min
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9.
What is the half-life of gold-198?
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10.
Separation
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11.
Activity Full Strength Source
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12.
Field Size
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13.
Tumor Dose (Dmax Dose)
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14.
If setting a 10 x 10 field size using an isocentric technique, the field size on the patient’s skin would be?
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15.
ISCF (for Extended Distance Set-ups)
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16.
A patient is prescribed a dose of 180 cGy at a depth of 10 cm with 10 MV photons at 100 cm SSD. The PDD is 60%. Calculate the dose to the depth of maximum dose.
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17.
Calculate the Gap: Field 1- Length = 17 cm, Width = 6 cm, Depth = 3 cm, SSD = 92 cm; Field 2- Length = 15 cm, Width = 12.5 cm, Depth = 3 cm, SSD = 91 cm.
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18.
What is the field size on a film if the collimator setting is 7 cm X 19 cm and the magnification factor is 1.33x?
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19.
What is the practical range in tissue for a 10 MeV electron beam?
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20.
What is the half-life of cesium-137?
A.
1,622 years (W/L, pg. 303).
B.
Physical dimensions set on the collimators of the therapy unit that determine the size of the treatment field at a reference distance (W/L, pg. 494).
C.
20 cGy/min. (Mosby’s RT Study Guide, pg. 108).
D.
2.7 days (W/L, pg. 303).
E.
(102.4/x) = (85.5/100)^2; x = 140 cGy/Min.
F.
HA = 180 - 2(wedge angle) (RT Essentials, pg. 135)
G.
The distance from the source of photons to the patient’s skin surface (W/L, pg. 494).
H.
Smaller.
I.
0.5 to 2.0 cGy/min. (Mosby’s RT Study Guide, pg. 108).
J.
The measurement of the patient’s thickness from the point of beam entry to the point of beam exit (W/L, pg. 494).
K.
30.0 years (W/L, pg. 303).
L.
Er =MeV/2; Er = 10 MeV/2; Er = 5 cm
M.
(17/2 x 3/92) + (15/2 x 3/91) (8.5 x .0326) + (7.5 x .0324) (.2771 + .0243) Gap= .52
N.
180/0.60 = 300 cGy.
O.
MeV/4 (W/L, pg. 555).
P.
A = (0.66mg/cm) x (active length of source in cm)
Q.
ISCF = (Reference source calibration distance)^2 / (Treatment SSD +Dmax)^2 *(Reference source calibration distance = Reference distance + Dmax for the energy) (W/L, pg. 508).
R.
9 X 25; 1.33 x 7 cm = 9.31 cm; 1.33 x 19 cm = 25.27 cm
S.
Greater.
T.
TD= (Given dose x PDD at depth of calculation)/100 (W/L, pg. 509).
Type the Question that corresponds to the displayed Answer.
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21.
Gap = (L1/2 × d/SSD1) + (L2/2 × d/SSD2) (W/L, pg. 516).
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22.
Given Dose= (TD/PDD) × 100 (W/L, pg. 509).
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23.
Ratio of the dose rate of a given field size to the dose rate of the reference field size (W/L, pg. 496).
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24.
The intersection of the axis of rotation of the gantry and the axis of rotation of the collimator for the treatment unit (W/L, pg. 494).
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25.
I1/I2 =(D2/D1 )^2 (W/L, pg. 497).
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26.
The dose rate of the machine; it is the amount of radiation “exposure” produced by a treatment machine or source as specified at a reference field size and a specified reference distance. (W/L, pg. 496).
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27.
The distance beneath the skin surface where the prescribed dose is to be delivered (W/L, pg. 494)
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28.
WA = 90 – (Hinge angle/2) (RT Essentials, pg. 135)
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29.
(SSD1+ d)^2 / (SSD1+ Dmax )^2 ×(SSD2 )+ Dmax )^2/(SSD2+ d)^2 *New PDD = Old PDD x Mayneord F-factor (W/L, pg. 508).
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30.
Equivalent Square= (4(L ×W)) / (2(L +W)) (W/L, pg. 498).

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