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Bontrager 4 & 5 Test

Enter the letter for the matching Answer
incorrect
1.
PA PROJECTION: WRIST Patient Position
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2.
LATERAL PROJECTION: ELBOW Patient Position
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3.
LATERAL PROJECTION: WRIST Part Position
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4.
PA OBLIQUE PROJECTION: HAND Anatomy Demonstrated
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5.
AP PROJECTION: AC JOINTS Anatomy Demonstrated
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6.
Radial deviation - why is it used?
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7.
PA OBLIQUE PROJECTION: HAND CR
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8.
PA OBLIQUE PROJECTION: WRIST Anatomy Demonstrated
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9.
AP projections of the elbow a lateral rotation:
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10.
AP PROJECTION: AC JOINTS Minimum SID — IR size — KV
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11.
AP PROJECTION: FOREARM Patient Position
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12.
LATERAL PROJECTION: WRIST Anatomy Demonstrated
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13.
LATERAL PROJECTION: FOREARM Patient Position
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14.
PA PROJECTION: HAND Part Position
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15.
CAST CONVERSiON Fiberglass cast
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16.
PA OBLIQUE PROJECTION: WRIST Minimum SID — IR size — KV
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17.
AP PROJECTION: ELBOW Patient Position
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18.
PA AND PA AXIAL SCAPHOID—WITH ULNAR DEVIATION: WRIST CR
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19.
SCAPULAR Y LATERAL—ANTERIOR OBLIQUE POSITION: SHOULDER CR
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20.
AP PROJECTION: AC JOINTS Part Position
A.
CR perpendicular to IR, directed to third MCp joint
B.
separates the radius and ulna
C.
Pronate hand with palmar surface in contact with IR; spread fingers slightly. •Align long axis of hand and forearm with long axis of IR. •Center hand and wrist to IR.
D.
Seat patient at end of table with elbow flexed about 90° and hand and wrist resting on IR, palm down. Drop shoulder so that shoulder, elbow, and wrist are on same horizontal plane
E.
Minimum SID—72 inches (183 cm) • IR size—35 × 43 cm (14 × 17 inches), crosswise, or (10 × 12 inches) crosswise for unilateral exposures Digital systems—70 to 80 kV range
F.
Seat patient at end of table, with elbow flexed 90°
G.
A less frequent PA wrist projection involves the radial deviation movement that opens and best demonstrates the carpals on the opposite, or ulnar, side of the wrist—the hamate, pisiform, triquetrum, and lunate.
H.
Seat patient at end of table, with elbow fully extended, if possible.
I.
Increase 3 kV to 4 kV
J.
Seat patient at end of table, with elbow flexed 90°
K.
Distal radius and ulna, carpals, and at least the midmetacarpal area are visible.
L.
Position patient to direct CR to midway between AC joints. • Center midline of IR to CR (top of IR should be approximately 2 inches [5 cm] above shoulders).
M.
Angle CR 10° to 15° proximally, along long axis of forearm and toward elbow. (CR angle should be perpendicular to long axis of scaphoid.) • Center CR to scaphoid. (Locate scaphoid at a point 2 cm [34 inch] distal and medial to radial styloid process.)
N.
Anatomy Demonstrated: • Both AC joints, entire clavicles, and SC joints are demonstrated.
O.
Distal radius, ulna, carpals, and at least to midmetacarpal area are visible. • Trapezium and scaphoid should be well visualized, with only slight superimposition of other carpals on their medial aspects.
P.
Minimum SID—40 inches (102 cm) • IR size—24 × 30 cm (10 × 12 inches),lengthwise 65 TO 70 kV range
Q.
Adjust hand and wrist into a true lateral position, with fingers comfortably flexed; if support is needed to prevent motion, use a radiolucent support block and sandbag, and place block against extended hand and fingers
R.
CR perpendicular to IR, directed to scapulohumeral joint (2 or 2-1/2 inches [5 or 6 cm] below top of shoulder)
S.
Oblique projection of the entire hand and wrist and about 2.4 cm (1 inch) of distal forearm are visible.
T.
Seat patient at end of table, with hand and arm fully extended and palm up (supinated).
Type the Answer that corresponds to the displayed Question.
incorrect
21.
The expanded distal end of the spine of the scapula that extends superiorly and posteriorly to the glenoid cavity (fossa).
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22.
In this rotation position, the epicondyles of the distal humerus are perpendicular to the iR, placing the humerus in a true lateral position. The hand must be pronated and the elbow adjusted to place the epicondyles perpendicular to the iR
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23.
Located anteriorly on proximal humerus in a true AP projection.
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24.
This rotation position represents a true aP projection of the humerus in the anatomic position
Type the Question that corresponds to the displayed Answer.
incorrect
25.
CR perpendicular to IR, directed to mid-elbow joint, which is approximately 2 cm (3/4 inch) distal to midpoint of a line between epicondyles
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26.
Center first MCp joint to CR and to center of IR. Immobilize other fingers with tape to isolate thumb if necessary.
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27.
CR perpendicular to IR, directed to midcarpal area
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28.
CR perpendicular to IR, directed to third MCp joint

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